一串奇怪的数
题目描述:给你一串密文, 它的加密代码(附件中)也已经截取, 现得知解密后是某产品的密钥. 下面是密文内容:
- 149 -234 -157 -132 -187 -140 -157 -241 -158 -177 -85 -215 -180 -187 -173 -218 -161 -183 -133 -226 -136 -171 -126 -169 -155 -96 -169 -240 -163 -153 -137 -111 -123 -191 -151 -213 -151 -142 -152 -208 -118 -137 -136 -244 -157 -168 -187 -201 -170 -176 -192 -209 -205 -174 -163 -189 -126 -133 -148 -194 -145 -212 -170 -155 -148 -165 -167 -206 -171 -177 -88 -173 -125 -129 -129 -235 -121 -190 -161 -165
下面是该产品一些公开的密钥
T5Q-4HQ-KEY-KP0-HAH
FCK-MNO-KEY-O8W-HAH
MRS-L1H-KEY-FU3-HAH
请解密密文得到该产品的密钥(最后一组密钥即为key)
1 | encode |
过程还好,就是密钥是空的服了
#coding:utf-8
import hashlib
def md5(s):
return hashlib.md5(s.encode('ascii')).hexdigest()
def evalCrossTotal(strMd5):
r = 0
for i in strMd5:
r += int("0x%s" % i, 16)
return r
def encryptString(strString, strPasswd):
strPasswdMd5 = md5(strPasswd)
intMd5 = evalCrossTotal(strPasswdMd5)
r = []
for i in range(len(strString)):
r.append(
ord(strString[i]) + \
int("0x%s" % strPasswdMd5[i%32], 16) - \
intMd5
)
intMd5 = evalCrossTotal(
md5(strString[:(i+1)])[:16] + \
md5(str(intMd5))[:16]
)
return " ".join(map(lambda x: str(x), r))
def decryptString(r,strPasswd):
strPasswdMd5 = md5(strPasswd)
intMd5 = evalCrossTotal(strPasswdMd5)
m =''
for i in range(len(r)):
m += chr(r[i]+intMd5 - int("0x%s" % strPasswdMd5[i%32], 16))
intMd5 = evalCrossTotal(
md5( m[:i+1])[:16] + \
md5( str(intMd5))[:16]
)
print(m)
def main():
s="-149 -234 -157 -132 -187 -140 -157 -241 -158 -177 -85 -215 -180 -187 -173 -218 -161 -183 -133 -226 -136 -171 -126 -169 -155 -96 -169 -240 -163 -153 -137 -111 -123 -191 -151 -213 -151 -142 -152 -208 -118 -137 -136 -244 -157 -168 -187 -201 -170 -176 -192 -209 -205 -174 -163 -189 -126 -133 -148 -194 -145 -212 -170 -155 -148 -165 -167 -206 -171 -177 -88 -173 -125 -129 -129 -235 -121 -190 -161 -165"
r=eval('[%s]' %s.replace(' ',','))
print(len(r))
pw = ''
decryptString(r,pw)
if __name__ == '__main__':
main()